【单选题】【消耗次数:1】
设<img src=https://huaweicloudobs.ahjxjy.cn/EB9273FC2A401B07F21A5963DABFEFF5.png title=$(CD2XN5{(UWHO8B33]E%9M.png alt=$(CD2XN5{(UWHO8B33]E%9M.png/>( )
<img src=https://huaweicloudobs.ahjxjy.cn/E2ED9355CC0DDB1BCDE4B3C0EAFE7BC5.png title=%1NL@3XVVXTRAI$)(WMWNBK.png alt=%1NL@3XVVXTRAI$)(WMWNBK.png/>
<img src=https://huaweicloudobs.ahjxjy.cn/0B3FD4B10E77DD298A2AC48D8F97B870.png title=F3~R$`{@AAM[AI(I4KY%DD8.png alt=F3~R$`{@AAM[AI(I4KY%DD8.png/>
<img src=https://huaweicloudobs.ahjxjy.cn/B8F060494492DB03EA5413B79DA41A95.png title=GXCDR5NTLIYIBK0XM`W{V8U.png alt=GXCDR5NTLIYIBK0XM`W{V8U.png/>
<img src=https://huaweicloudobs.ahjxjy.cn/6723BA3042BEF4CA483C59A215250520.png title=O}L}_L(P}{39E{@~RS8FZNL.png alt=O}L}_L(P}{39E{@~RS8FZNL.png/>
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随机题目
【单选题】 <img title=无标题417.jpg alt=无标题417.jpg src=https://huaweicloudobs.ahjxjy.cn/3C8C33825C525C3909845A7ADAD98762.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/96549CE1F66A72FC71857F65B2064550.png data-tex=\dot { { U }_{ C } } =22.36\angle { -63.45 }^{ 0 }V\quad ,\quad \dot { { I }_{ 1 } } =5\angle { 53.1 }^{ 0 }A\quad ,\quad \quad \dot { { I }_{ 2 } } =-5\sqrt { 2 } \angle { 8.1 }^{ 0 }A/>
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/33EF9120DD52B1802F531C0B0427B092.png data-tex=\dot { { U }_{ C } } =22.36\angle { -63.45 }^{ 0 }V\quad ,\quad \dot { { I }_{ 1 } } =-5\angle { 53.1 }^{ 0 }A\quad ,\quad \quad \dot { { I }_{ 2 } } =-5\sqrt { 2 } \angle { 8.1 }^{ 0 }A/>
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/66E63DC73B03D3683D6E649DBD0F4DEC.png data-tex=\dot { { U }_{ C } } =22.36\angle { -63.45 }^{ 0 }V\quad ,\quad \dot { { I }_{ 1 } } =5\angle { 53.1 }^{ 0 }A\quad ,\quad \quad \dot { { I }_{ 2 } } =5\sqrt { 2 } \angle { 8.1 }^{ 0 }A/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/1B0CC7824E4E369D6B1848814659A0AC.png data-tex=\dot { { U }_{ C } } =22.36\angle { -63.45 }^{ 0 }V\quad ,\quad \dot { { I }_{ 1 } } =5\sqrt { 2 } \angle { 53.1 }^{ 0 }A\quad ,\quad \quad \dot { { I }_{ 2 } } =-5\angle { 8.1 }^{ 0 }A/>
【单选题】 <img title=无标题51.jpg alt=无标题51.jpg src=https://huaweicloudobs.ahjxjy.cn/0251D83C45A416CD7471540F7BA95E29.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/3541324779CB2E2324F918A4176E489C.png data-tex={ u }_{ 1 }={ L }_{ 1 }\frac { d{ i }_{ 1 } }{ dt } +M\frac { d{ i }_{ 2 } }{ dt } \\ { u }_{ 2 }={ L }_{ 2 }\frac { d{ i }_{ 2 } }{ dt } +M\frac { d{ i }_{ 1 } }{ dt } />
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/1C2553866C1758912E84F5BB8CC2C143.png data-tex={ u }_{ 1 }={ L }_{ 1 }\frac { d{ i }_{ 1 } }{ dt } +M\frac { d{ i }_{ 1 } }{ dt } \\ { u }_{ 2 }={ L }_{ 2 }\frac { d{ i }_{ 2 } }{ dt } +M\frac { d{ i }_{ 2} }{ dt } />
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/D0867A802BF3EEAD0AF1B2DA98635E75.png data-tex={ u }_{ 1 }={ L }_{ 1 }\frac { d{ i }_{ 2 } }{ dt } +M\frac { d{ i }_{ 1 } }{ dt } \\ { u }_{ 2 }={ L }_{ 2 }\frac { d{ i }_{ 2 } }{ dt } +M\frac { d{ i }_{ 1 } }{ dt } />
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/DF5F5CA162C4A650D65C23C31464B4E1.png data-tex={ u }_{ 1 }={ L }_{ 1 }\frac { d{ i }_{ 1 } }{ dt } +M\frac { d{ i }_{ 2 } }{ dt } \\ { u }_{ 2 }={ L }_{ 2 }\frac { d{ i }_{ 1 } }{ dt } +M\frac { d{ i }_{ 2 } }{ dt } />
【单选题】 <img title=无标题510.jpg alt=无标题510.jpg src=https://huaweicloudobs.ahjxjy.cn/A39E160380B82FC26AD5BD65F42C96E2.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/1F81EC0518938BA76A80E3EBFB772D2E.png data-tex=[{ R }_{ 1 }+j\omega ({ L }_{ 1 }-M)+{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 2 } } =\dot { { U }_{ 1 } } \\ -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } +[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)+R+j\omega M-j\frac { 1 }{ \omega C } ]\dot { { I }_{ 2 } } =0/>
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/1665B2B92A716A59AA7889FFB2C22DAF.png data-tex=[{ R }_{ 1 }+j\omega ({ L }_{ 1 }-M)+{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 2 } } =\dot { { U }_{ 1 } } \\ -[{ R }_{ 1 }+j\omega ({ L }_{ 1 }-M)]\dot { { I }_{ 1 } } +[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)+R+j\omega M-j\frac { 1 }{ \omega C } ]\dot { { I }_{ 2 } } =0/>
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/A0C5575497B6B2297F7D95C9E867756D.png data-tex=[{ R }_{ 1 }+j\omega ({ L }_{ 1 }-M)+{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 2 } } =\dot { { U }_{ 1 } } \\ -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } +[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)+R+j\omega M+j\frac { 1 }{ \omega C } ]\dot { { I }_{ 2 } } =0/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/8F29A9FCFFFB39EE813F2A0F49FB7469.png data-tex=[{ R }_{ 1 }+j\omega ({ L }_{ 1 }-M)+{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 1 } } -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 2 } } =\dot { { U }_{ 1 } } \\ -[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)]\dot { { I }_{ 2 } } +[{ R }_{ 2 }+j\omega ({ L }_{ 2 }-M)+R+j\omega M-j\frac { 1 }{ \omega C } ]\dot { { I }_{ 21} } =0/>
【单选题】 <img title=无标题44.jpg alt=无标题44.jpg src=https://huaweicloudobs.ahjxjy.cn/222B871269010B4A027124A6229482B4.jpg/>
①  u<img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/A61758EB2BFA56FBDC2CD01AAE14098A.png data-tex=u=90\sqrt { 2 } sin(314t-{ 8.7 }^{ 0 })V/>
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③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/058C7EE5BFE4A559626CC50BACBD52EB.png data-tex=u=64\sqrt { 2 } sin(50t-{ 8.7 }^{ 0 })V/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/CEA2F282D0CAB1DE63C7939C72ED6695.png data-tex=u=64\sqrt { 2 } sin(314t-{30}^{ 0 })V/>
【单选题】 <img title=无标题65.jpg alt=无标题65.jpg src=https://huaweicloudobs.ahjxjy.cn/90D0778C7889A7A063EE28D339BD280C.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/A33618F57A0BFEDDEEAFC91D2E7059CC.png data-tex={ U }_{ l }=416.3V/>
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/13AE67CF84BAC20C550079E89CE305D9.png data-tex={ U }_{ l }=461.3V/>
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/E1341C93714922B632DEBCE4313CF8C6.png data-tex={ U }_{ l }=400V/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/3E1091706B8F7374BA8BE14B1FEDF956.png data-tex={ U }_{ l }=358.2V/>
【单选题】 <img title=无标题54.jpg alt=无标题54.jpg src=https://huaweicloudobs.ahjxjy.cn/7F0622F95531F92809AE5B24931DBDF7.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/F28D6C1790C478882B49B794CEEED3B8.png data-tex=\dot { { U }_{ OC } } =10\angle { 0 }^{ 0 }V,{ Z }_{ eq }=(3+j7.5)\Omega />
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/FD6E39099501DC0CDCAA0EF923B677D1.png data-tex=\dot { { U }_{ OC } } =15\angle { 0 }^{ 0 }V,{ Z }_{ eq }=(7.5+j3)\Omega />
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/20B80DAC0CB9863EAB2AFB4CA7AB06AC.png data-tex=\dot { { U }_{ OC } } =15\angle { 0 }^{ 0 }V,{ Z }_{ eq }=(3+j7.5)\Omega />
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/6DA2D6FD6AE82E90AE1FC737940BD7BA.png data-tex=\dot { { U }_{ OC } } =15\angle { 0 }^{ 0 }V,{ Z }_{ eq }=(3-j7.5)\Omega />
【单选题】 <img title=无标题424.jpg alt=无标题424.jpg src=https://huaweicloudobs.ahjxjy.cn/6F29F45EA643270C06EBDBB515AAB9EE.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/80C14D152614D713405E83B0DE81FDF4.png data-tex={ Z }_{ L }=(0.6+j0.2)\Omega ,{ P }_{ max }=416.6W/>
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/8E33BDBE346DA6ACF7456637D0C52813.png data-tex={ Z }_{ L }=(0.6-j0.2)\Omega ,{ P }_{ max }=416.6W/>
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/B0E1DB55162B982797B8F32573286D69.png data-tex={ Z }_{ L }=(0.2+j0.6)\Omega ,{ P }_{ max }=416.6W/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/FE85C5E2EFA64184ADBB6C5059BD1EFE.png data-tex={ Z }_{ L }=(0.6+j0.2)\Omega ,{ P }_{ max }=46.6W/>
【单选题】 <img title=无标题410.jpg alt=无标题410.jpg src=https://huaweicloudobs.ahjxjy.cn/9F49FB2190789FFD2F9D5E8D8362F0F8.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/3F6EE769CB63FF491B3AE9C590CFC4C4.png data-tex=(a)Z=j0.05\Omega ,Y=-j20S\\ (b)Z=(1.3+j4.8)\Omega ,Y=(4.8-j0.2)S/>
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/5F08668FE74FE9D6D35D5204C07C59E8.png data-tex=(a)Z=j20\Omega ,Y=-j0.05S\\ (b)Z=(1.3+j4.8)\Omega ,Y=(4.8-j0.2)S/>
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/AF74771289508ADB6C160414B06F2966.png data-tex=(a)Z=j20\Omega ,Y=-j0.05S\\ (b)Z=(5+j4.8)\Omega ,Y=(4.8-j0.2)S/>
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/717FA115D6F41ABBABC72F1D625711C4.png data-tex=(a)Z=j20\Omega ,Y=-j0.05S\\ (b)Z=(1.3+j4.8)\Omega ,Y=(0.2-j0.2)S/>
【单选题】 <img title=无标题426.jpg alt=无标题426.jpg src=https://huaweicloudobs.ahjxjy.cn/F0951855E573A97AEF1C967B473ECBA6.jpg/>
①  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/D5A6F8981882EB832EF1EF2D47534C8D.png data-tex=cos\varphi =0.5,R=15\Omega ,{ X }_{ L }=16.1\Omega />
②  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/5C4C3196D1110576D4461A65FB0E9490.png data-tex=cos\varphi =0.682,R=15\Omega ,{ X }_{ L }=16.1\Omega />
③  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/5723BC0EA51626B821293278E60D4474.png data-tex=cos\varphi =0.682,R=16.1\Omega ,{ X }_{ L }=15\Omega />
④  <img class=jc-formula style=vertical-align: middle; src=https://huaweicloudobs.ahjxjy.cn/24C4607E78F40A9829ADB1518F6E1FE4.png data-tex=cos\varphi =0.6,R=15\Omega ,{ X }_{ L }=16.1\Omega />
【单选题】 2-8 应用结点电压法计算题图2-8所示电路中的电流<img class=jc-formula data-tex=I src=https://huaweicloudobs.ahjxjy.cn/CFE0FB65A01B097AD2957AEA6E52A94D.png style=vertical-align: middle;/>。<img src=https://huaweicloudobs.ahjxjy.cn/7CA329FC3DF3FA2AA06E36F5DB291BEA.png title=2-8.PNG alt=2-8.PNG/>
①  <img class=jc-formula data-tex=3A src=https://huaweicloudobs.ahjxjy.cn/0FCED515C1D88658429553759006411C.png style=vertical-align: middle;/>
②  <img class=jc-formula data-tex=-3A src=https://huaweicloudobs.ahjxjy.cn/CBCC81C9D235BC0EEF9EF6674C1648A7.png style=vertical-align: middle;/>
③  <img class=jc-formula data-tex=6A src=https://huaweicloudobs.ahjxjy.cn/5B9CFDF984B953D6664E9F9791E15EC3.png style=vertical-align: middle;/>
④  <img class=jc-formula data-tex=-6A src=https://huaweicloudobs.ahjxjy.cn/6FE2A656B38982DCB448593927164113.png style=vertical-align: middle;/>