【多选题】【消耗次数：1】
_____________ , the meeting was closed.
①
Nobody having any more to say
②
Nobody have any more to say
③
Since nobody had any more to say
④
Since nobody having any more to say
参考答案：
复制
纠错
相关题目
【单选题】
So clear was his _____ of the case that others had no more to say.
①
attitude
②
presentation
③
comment
④
remark
【单选题】
Marlin is an independent man who is not about ＿＿＿＿＿ on his parents any more.
①
having relied
②
to rely
③
relying
④
to have relied
【单选题】
Marlin is an independent man who is not about ＿＿＿＿＿ on his parents any more.
①
having relied
②
to rely
③
relying
④
to have relied
【单选题】
Air is very important, _________ we cannot live any more.
①
without that
②
no which
③
where
④
without which
【单选题】
An institution that properly carries the name university is a more comprehensive and complex institution than any other kind of higher education ____.
①
settlement
②
establishment
③
construction
④
structure
【单选题】
An institution that properly carries the name university is a more comprehensive and complex institution than any other kind of higher education _____.
①
settlement
②
establishment
③
construction
④
structure
【判断题】
Formal English is much more difficult to attain since it is subject to more restraints and requirements.
①
正确
②
错误
【单选题】
It’s better having short lines with more bank tellers.
①
[A] 如果银行出纳员多一些，不用排长队就好了。
②
[B]最好是排的队短一些，银行出纳员多一些。
③
[C]要是排的队短，银行出纳员最好多一些。
④
[D] 银行出纳员多一些，队就排得更短了。
随机题目
【单选题】
下面关于友元的描述中，错误的是（ ）。
①
友元函数可以访问该类的私有数据成员
②
一个类的友元类中的成员函数都是这个类的友元函数
③
友元可以提高程序的运行效率
④
类与类之间的友元关系可以继承
【单选题】
多继承的构造顺序序可分为如下4步:①所有非虚基类的构造函数按照它们被继承的顺序构造;②所有虚基类的构造函数按照它们被继承的顺序构造;③所有内嵌对象的构造函数按照它们声明的顺序构造;④派生类自己的构造函数体;这4个步骤的正确顺序是（ ）
①
④③①②
②
②④③①
③
②①③④
④
③④①②
【单选题】
下面（ ）的叙述不符合赋值兼容规则。
①
派生类的对象可以赋值给基类的对象
②
基类的对象可以赋值给派生类的对象
③
派生类的对象可以初始化基类的对象
④
派生类的对象的地址可以赋值给指向基类的指针
【单选题】
以下类模板定义正确的为（ ）。
①
templateclass T,int i=0
②
templateclass T,class int i
③
templateclass T,typename T
④
templateclass T1,T2